Question: A screw gauge has least count of 0.01 mm and there are 50 divisions in its circular scale. The pitch of the screw gauge is:
| A | 0.01 mm |
| B | 0.25 mm |
| C | 0.5 mm |
| D | 1.0 mm |
Solution:
To find the pitch of the screw gauge, we can use the formula for the least count:
Least count = \( \frac{\text{Pitch}}{\text{Number of divisions on the circular scale}} \)
Given that the least count is 0.01 mm and there are 50 divisions on the circular scale, we can substitute these values into the formula:
\( 0.01 = \frac{\text{Pitch}}{50} \)
Now, solving for the pitch:
\( \text{Pitch} = 0.01 \times 50 = 0.5 \, \text{mm} \)
Thus, the pitch of the screw gauge is 0.5 mm.
Correct Answer: C) 0.5 mm
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